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We can use a superscript star to indicate that the unit vector is evaluated at the failure point. It then follows that the coordinates of the failure point must be xi = i (16.45)

Wednesday fourth day of racing, light winds and hot 8:30 Porridge for breakfast with 500ml water 10:00 A tuna salad sandwich with 500 ml water 11:00 Race 10 followed by a carbohydrate drink (5 grams of carbohydrate per 100ml fluid) 12:00 Race 11 followed by a carbohydrate drink (5 grams of carbohydrate per 100ml fluid) 13:00 Race 12 followed by a carbohydrate drink (5 grams of carbohydrate per 100ml fluid) 15:00 Return ashore for tuna salad sandwich and 500ml water 18:00 Couscous with chicken salad and 500ml water Thursday fifth day of racing, strong winds 8:30 Porridge for breakfast with orange juice 11:00 Race 13 followed by 500ml carbohydrate drink (8 grams of carbohydrate per 100ml fluid) 12:00 Race 14 followed by 500ml carbohydrate drink (8 grams of carbohydrate per 100ml fluid) 14:00 Return ashore for large spaghetti Bolognaise and 500ml water 19:00 White fish with new potatoes plus lots of vegetables and 500ml water Friday sixth day of racing, medium winds 9:30 Porridge for breakfast with orange juice plus 500ml water 11:00 Race 15 followed by 500ml carbohydrate drink (5 grams of carbohydrate per 100ml fluid) 13:00 Tuna baguette with salad with 500ml water, then pack boat 17:00 Prize giving buffet then drive home.

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You know that RtlGetElementGenericTable is returning the value of one of these pointers to the caller, but not before it is incremented by 12. Note that 12 also happens to be the total size of those three pointers. You have established that RtlGetElementGenericTable takes two parameters and that the first is the table data structure pointer and the second is an index into the table. You can safely assume that it returns the element through the return value.

The Rackwitz algorithm then proceeds in six iterative steps (Ang and Tang 1990): 1. Assume initial values of xi and compute the corresponding values of xi .

All of this leads to one conclusion. RtlGetElementGenericTable is returning a pointer to an element, and adding 12 simply skips the element s header and gets directly to the element s data. It seems very likely that this header is another three-pointer data structure just like that in offset +4 in the root data structure. Furthermore, it would make sense that each of those pointers point to other items with three-pointer headers, just like this one. One other thing you have learned here is that offset +10 is the index of the cached element the same element pointed to by the third pointer, at offset +c. The difference is that +c is a pointer to memory, and offset +10 is an index into the table, which is equivalent to an element number. To me, this is the thrill of reversing one by one gathering pieces of evidence and bringing them together to form partial explanations that slowly evolve into a full understanding of the code. In this particular case, we ve made progress in what is undoubtedly the most important piece of the puzzle: the generic table data structure.

There is one key element that s been quietly overlooked in all of this: What is the structure of this function Sure, you can treat all of those conditional and unconditional jumps as a bunch of goto instructions and still get away with understanding the flow of relatively simple code. On the other hand, what happens when there are too many of these jumps to the point where it gets hard to keep track of all of them You need to start thinking the code s logic and structure, and the natural place to start is by trying to logically place all of these conditional and unconditional jumps. Remember, the assembly language code you re reversing was generated by a compiler, and the original code was probably written in C. In all likelihood all of this logic originated in neatly organized if-else statements. How do you reconstruct this layout Let s start with the first interesting conditional jump in Listing 5.2 the JE that goes to ntdll.7C962554 (I m ignoring the first two conditions that jump to ntdll.7C962559 because we ve already discussed those). How would you conditionally skip over so much code in a high-level language Simple, the condition tested in the assembly language code is the opposite of what was

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