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ULONG AdjustedElementToGet = ElementToGet + 1; if (ElementToGet == 0xffffffff || AdjustedElementToGet > Table->TotalElements) return 0;

Both the above approaches give the same nal equation for the reliability index, but they do not describe how to nd the starred point at which Equations (16.38) or (16.43) are to be evaluated. As in any other non-linear minimization problem, the choice of algorithm depends on the speci c function to be minimized and the constraints, and these will vary from problem to problem. There is a large literature on minimization problems; Press et al. (1992) give a good general introduction to the subject. Lin and Der Kiureghian (1991) examine a number of algorithms that have been proposed for the reliability problem. Rackwitz and his colleagues (Rackwitz 1976; Rackwitz and Fiessler 1978) proposed a technique that remains widely used. Ang and Tang (1990) included it in the second volume of their book, and it is described below. Equation (16.26) in Section 16.3.1 de nes G as the gradient of the failure function with respect to the primed variables. This can be normalized into a unit vector : g xi g xi

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How can you tell whether ElementToGet + 1 was calculated within the if statement or if it was calculated into a variable first You don t really know for sure, but when you look at all the references to EBX in Listing 5.2 you can see that the value ElementToGet + 1 is being used repeatedly throughout the function. This suggests that the value was calculated once into a local variable and that this variable was used in later references to the incremented value. The compiler has apparently assigned EBX to store this particular local variable rather than place it on the stack. On the other hand, it is also possible that the source code contained multiple copies of the statement ElementToGet + 1, and that the compiler simply

5

G (GT G)1/2

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optimized the code by automatically declaring a temporary variable to store the value instead of computing it each time it is needed. This is another case where you just don t know this information was lost during the compilation process. Let s proceed to the next code sequence:

i =

7C962501 7C962503 7C962505 7C962507 7C962509 7C96250B 7C96250D 7C96250F 7C962511 CMP ESI,EBX JE SHORT ntdll.7C962554 JBE SHORT ntdll.7C96252B MOV EDX,ESI SHR EDX,1 CMP EBX,EDX JBE SHORT ntdll.7C96251B SUB ESI,EBX JE SHORT ntdll.7C96254E

This section starts out by comparing ESI (which was taken earlier from offset +10 at the table structure) against EBX. This exposes the fact that offset +10 also points to some kind of an index into the table (because it is compared against EBX, which you know is an index into the table), but you don t know exactly what that index is. If ESI == EBX, the code jumps to ntdll.7C962554, and if ESI <= EBX, it goes to ntdll.7C96252B. It is not clear at this point why the second jump uses JBE even though the operands couldn t be equal at this point or the first jump would have been taken. Let s first explore what happens in ntdll.7C962554:

(16.44)

This code does EAX = EAX + 12, and unconditionally jumps to ntdll. 7C96255B. If you go back to Listing 5.2, you can see that ntdll.7C96255B is right near the end of the function, so the preceding code snippet simply returns EAX + 12 to the caller. Recall that EAX was loaded earlier from the table structure at offset +C, and that while dissecting RtlInitializeGenericTable, you were working under the assumption that offsets +4, +8, and +C are all pointers into the same three-pointer data structure (they were all initialized to point at offset +4). At this point one, of these pointers is incremented by 12 and returned to the caller. This is a powerful hint about the structure of the generic tables. Let s examine the hints one by one:

You know that there is a group of three pointers starting in offset +4 in the root data structure. You know that each one of these pointers point into another group of three pointers. Initially, they all point to themselves, but you can safely assume that this changes later on when the table is filled.

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