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Some kind of interpolation is required if you have access only to data of discrete, separate points but you want to know the value somewhere in between these points. Such a situation is presented in the left part of Figure 5-17. For some separate (read: integer) X values, you know the exact Y value. For X=2, you know Y=10, and for X=3, you know Y=30. But you don t know how much Y would be for X=2.7.

Figure 9-1. The if statement The following code shows examples of if statements: // With a simple statement if( x <= 10 ) z = x 1;

Figure 3 38. On the Display menu, you can choose the view for your item. This menu allows you to choose how the folder displays its contents to web site visitors. The available options are Standard view: This is the default option; the folder will show its contents as in Figure 3-39.

20 10

46 35

// With a block if( x >= 20 ) { x = x 5; y = x + z; }

Summary view: With this option, the folder will show its contents as in Figure 3-40.

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Figure 5-17. Linear interpolation: easy and general example Using linear interpolation, you find the Y value for X=2.7 by connecting the exact points with a line, as in Figure 5-17. Linear interpolation always starts by expressing your X value between 0 and 1, where 0 corresponds to the lower X value of which you know the exact Y value (2 in this case) and 1 corresponds to the higher X value (3 in this case). In the example case where you want to find the Y value corresponding to X=2.7, this would yield 0.7, meaning 70 percent between 2 and 3. In the left part of Figure 5-17, 0 percent corresponds to a Y value of 10, 100 percent corresponds to a Y value of 20, so 70 percent corresponds to Y=17. It s easy to see, but how about the right part of that image Fourteen gives a relative value of 0.33, because it is 33 percent between 13 and 16. But how much is 33 percent between 35 and 46 Obviously, you want some code to calculate this for you. First you want some code to find the relative value between 0 and 1. From your X value, you first subtract the lower X value so your minimum value becomes 0. Next, you have to scale it down so your maximum value becomes 1. You can do this by dividing with the difference between the max and min X values. Wow. This is how it s done for the left part of Figure 5-17:

int x = 5; if( x ) { ... }

2 .7

Tabular view: If you choose this option, the folder will show its contents as in Figure 3-41.

2 .7 2 3 2

The if...else statement implements a two-way branch. The syntax for the if...else statement is shown here, and is illustrated in Figure 9-2. If TestExpr evaluates to true, Statement1 is executed. If it evaluates to false, Statement2 is executed instead. if( TestExpr ) Statement1 else Statement2

0 .7 1

Figure 3 41. Tabular view Thumbnail view: If you choose this option, the folder will show its contents as in Figure 3-42.

0 .7

Figure 9-2. The if...else statement The following is an example of the if...else statement: if( x <= z = x else { x = x y = x } 10 ) 1;

Select a content item as default view: If you choose this option, a panel with a list of items contained in that folder will appear, as shown in Figure 3-43. Not all content types are included in this list (e.g., folders are not available). You can choose one item from the list for example, a page with some text that presents that section and this will become the default view for that folder.

Next, you do exactly the opposite to find the corresponding Y value: you first scale this value up (by multiplying by the difference between the min and max Y values), and you add the lower Y value:

0.7 * (20 10) 10

5; + z;

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